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ProvedGeometry·1838

Isoperimetric Problem

Among plane figures with a fixed perimeter, the circle encloses the greatest area.

Formula

Isoperimetric inequality
L24πAL^2\ge 4\pi A

Among all simple closed curves of length L enclosing area A, the circle is the unique maximizer of A for given L.

Equality case
L2=4πAγ is a circleL^2=4\pi A\quad\Longleftrightarrow\quad\gamma\text{ is a circle}

Equality holds if and only if the curve is a circle — proved rigorously by Weierstrass via the calculus of variations.

Higher-dimensional generalization
ΩnnnωnΩn1,ωn=Bn|\partial\Omega|^n\ge n^n\omega_n\,|\Omega|^{n-1},\qquad\omega_n=|B^n|

In Rⁿ, among bodies of given volume, the ball has the least surface area. Equality iff Ω is a ball.

Summary

The isoperimetric problem is one of the oldest optimization problems in geometry. Its visual statement is immediate: deform any closed curve while holding perimeter fixed, and the enclosed area is maximized exactly when the curve becomes a circle.

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