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PartialCombinatorics·1950

Hadwiger-Nelson Problem

Determine how many colors are needed to color the plane so points distance 1 apart differ.

Formula

Chromatic number of the plane
5χ(R2)75\le \chi(\mathbb{R}^2)\le 7

The minimum number of colors needed so no two points at distance 1 share a color lies between 5 and 7.

de Grey lower bound (2018)
GR2:  χ(G)5,V(G)=1581\exists\, G\subset\mathbb{R}^2:\;\chi(G)\ge 5,\quad |V(G)|=1581

Aubrey de Grey constructed a unit-distance graph on 1,581 vertices requiring 5 colors, breaking the 1950s bound of 4.

Hexagonal upper bound
χ(R2)7(hexagonal 7-coloring with diameter <1)\chi(\mathbb{R}^2)\le 7\quad\text{(hexagonal 7-coloring with diameter }<1\text{)}

Coloring the plane with regular hexagons of diameter slightly less than 1 gives a valid 7-coloring — unimproved since 1950.

Summary

The chromatic number of the plane is known to be at least 5 and at most 7. The problem is easy to draw as a unit-distance graph but remains open after decades.

Sources

Videos